Monday, October 3, 2011

So here are the answers to the challenge from the last post.  Sorry this wasn't posted right away.

Four of the possibilities (and the strongest ones) are in the Consecutive Run section of the card:
There are lots of choices here.  This is where you would most likely end up.

55 666 7777 888 99
in all BAMS…of course.

11 22 111 222 DDDD
as:  88 99 888 9999 DDDD (3 suits…opposite dragon)
this is have the pairs of 88 BAMS and 99 you will need more 8's and 9's in dots if you use the red dragons....

111 222 3333 4444
as:  666 777 8888 9999 
8's and 9's in BAMS....6's and 7's in either CRAKS or DOTS

FFFF 1111 2222 DD
as:  FFFF 8888 9999 DD
You'll need Flowers and a PAIR of Green Dragons.

You can only use one number...either the eights OR nines..but you have an additional one of each number.
 11 DD  111 DDD 1111
of course you would do this hand with either 8's or 9's, depending upon what comes in
(That's why you keep the red dragon)

A long shot hand…but what if you suddenly pick a ton of jokers?  It could happen.
11111 2222 33333
This would be done with:
77777 8888 99999  (3 suits) depending upon whether more 9 BAMS or 8BAMS come in.

another longshot…if you DON'T get any more jokers:

998 99887 998877 (3 suits)

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